Fix: Ensure accurate typing state and simplify entry key check
Co-authored-by: aider (gemini/gemini-2.5-pro) <aider@aider.chat>
This commit is contained in:
12
tui.py
12
tui.py
@@ -520,8 +520,9 @@ class NametagScreen(Screen):
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def handle_input(self, c):
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button = self.get_button(c)
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if self.nametag_member:
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self.is_typing = True
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if c == KEY_ESCAPE: self.nametag_member = ''
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if c == KEY_ESCAPE:
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self.nametag_member = ''
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self.is_typing = False
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elif c == KEY_ENTER:
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if len(self.nametag_member) > 1:
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self.stdscr.addstr(15, 4, 'Printing...')
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@@ -531,8 +532,9 @@ class NametagScreen(Screen):
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self.state.current_screen = 'home'
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else: self.nametag_member = self.handle_text_input(c, self.nametag_member)
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elif self.nametag_guest:
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self.is_typing = True
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if c == KEY_ESCAPE: self.nametag_guest = ''
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if c == KEY_ESCAPE:
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self.nametag_guest = ''
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self.is_typing = False
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elif c == KEY_ENTER:
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if len(self.nametag_guest) > 1:
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self.stdscr.addstr(15, 4, 'Printing...')
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@@ -554,7 +556,7 @@ class NametagScreen(Screen):
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def is_entry_key(self, c):
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button = self.get_button(c)
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return not (self.nametag_member or self.nametag_guest) and button in ['m', 'g']
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return not self.is_typing and button in ['m', 'g']
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class LabelScreen(Screen):
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# This screen is complex, breaking it down into sub-states
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